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BC12D Brake Pedal Power

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  • BC12D Brake Pedal Power

    I am installing hydraulic brakes using Cleveland Wheel/Brake kit. I also plan to use the Cleveland 10-65 Master Cylinders by setting them up in a manner to use the existing pedals/ (pull) cables to activate the MC/Brakes . . Is there a way to determine how much leverage the existing pedals produce? Cleveland Engineers provided the pounds needed to activate the 10-65 MC / Brakes (350 lbs) but pointed out that the pedal/cable system leverage would also be a factor in determining the caliper/brakes would be able to produce 800 pounds .

    Thank you,

    bob

  • #2
    Here's one example of a similar application? https://vb.taylorcraft.org/forum/tay...es-for-N96872=

    You may have a 2nd Class Lever with load (cable to cylinders) between the force (pedal heel pad) and fulcrum (frame connection). How much force you can apply to the cable depends on where it's attached to the pedal. The closer to the fulcrum the more force on the cable from a given load at the pedal. https://en.wikipedia.org/wiki/Lever

    Figure out how hard you can push the pedals x mechanical advantage of ? to ? There's some sharp engineers here who can explain that better I bet. My last college Physics course was in 1965.

    Gary
    N36007 1941 BF12-65 STC'd as BC12D-4-85

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    • #3
      Your heel brake will provide more than enough force, put a pull gauge on the lower gear leg, put a bolt through the bell crank mount, run a cable down from the pedal to your scale, snug it up, climb in, press the pedal, measure the force. You dont need a whole lot of force for a T-craft unless you want to flip it on its back. DO NOT use dual puck calipers, waste of money and too much. I am running 850's and I can lock up the brakes on dirt. Tim
      Last edited by astjp2; 04-22-2019, 19:14.
      N29787
      '41 BC12-65

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      • #4
        Gary

        I am not familiar with a 2nd class lever system. Can you give an example?

        thank yo...

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        • #5
          Originally posted by swift1b View Post
          Gary

          I am not familiar with a 2nd class lever system. Can you give an example?

          thank yo...
          One would be the traditional Taylorcraft cable brake pedal. The load to move or lift is the cable resistance placed between the brace or fulcrum point where it rotates and attaches at the frame. The other component of the lever is the pedal we push on the opposite side of the load. If the load is midway between the force and fulcrum there's no mechanical advantage. If the cable's placed closer to the fulcrum or frame a given pressure and movement on the pedal is magnified and it takes less to pull harder on the cable.

          Another common 2nd class is the wheelbarrow. The tire is the fulcrum or bend point, the heavy load is in the bucket close to the tire, and the long handles let us lift that heavy load easier. The advantage comes from a long lift of the handles and a short lift of the bucket which lets lift more than we normally can and move it around.

          Gary
          N36007 1941 BF12-65 STC'd as BC12D-4-85

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          • #6
            Didn't you mean... If the load is midway between the force and fulcrum, the force applied to the load is doubled, the movement is halved.

            When you double the arm the moment doubles for a given force. Half the arm for a given moment and the force doubles.
            Scott
            CF-CLR Blog: http://c-fclr.blogspot.ca/

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            • #7
              Originally posted by Scott View Post
              Didn't you mean... If the load is midway between the force and fulcrum, the force applied to the load is doubled, the movement is halved.

              When you double the arm the moment doubles for a given force. Half the arm for a given moment and the force doubles.
              Yes, thanks for the correction Scott. The "Midway" was intended to be typed at the pressure but.....got to thank all for that.

              Gary
              N36007 1941 BF12-65 STC'd as BC12D-4-85

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